NODE cc42f44cD-H key exchange - how does it work?
ecarp@netcom.com (Ed Carp)Tue, 17 May 94 11:30:21 PDT
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I browsed through the (SCANT!) documentation that comes with rsaref-2.0. I
didn't find any decent programming examples, just a list of function
calls, which is next to useless without sample code, but that's beside the
point.
If I understand D-H right, both sides generate public keys from their
private keys, then just exchange public keys. Is that right? Or is there
something I'm missing?
- --
Ed Carp, N7EKG/VE3 ecarp@netcom.com 519/824-3307
Finger ecarp@netcom.com for PGP 2.3a public key an88744@anon.penet.fi
If you want magic, let go of your armor. Magic is so much stronger than
steel! -- Richard Bach, "The Bridge Across Forever"
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NODE 4d465b55Re: D-H key exchange - how does it work?
"Perry E. Metzger" <perry@imsi.com>Tue, 17 May 94 11:52:36 PDT
Ed Carp says:
> If I understand D-H right, both sides generate public keys from their
> private keys, then just exchange public keys. Is that right? Or is there
> something I'm missing?
Yes. Thats not the algorithm at all. D-H is based on the difficulty of
the discrete log problem, that is, the problem of inverting an
exponentiation modulo a large prime.
Its been a while, so I might be forgetting something here or
misstating -- someone correct me if I am wrong.
Suppose we have a field Z_p, where p is a prime. Suppose g is a
generator of the field. Alice generates a random number a. Bob
generates a random number b. Bob tells alice g^b, Alice tells Bob g^a.
Alice knows a and g^b, and thus generates g^(ab) trivially. Similarly,
Bob knows g^a and b, and trivially generates g^(ab). An interceptor
only knows g^a and g^b, and because the discrete log problem is hard
cannot get a or b easily, and thus cannot generate g^(ab).
g^(ab) is now a shared secret of Alice and Bob.
Perry