NODE e01f9061Re: IPG Algorith Broken!
paul@fatmans.demon.co.ukTue, 26 Nov 1996 09:55:30 -0800 (PST)
> > Ahh... an OTP isn't unbreakable. Its just so encredibly breakable that
> > you never know which break was the correct one ;)
>
> Note that Schneier says "perfect", not "unbreakable".
yes,
Perfect is a better term. Strictly speaking it is because there is no
finite unicity distance (the amount of ciphertext with which the
cipher can theoretically be broken). So, stricly speaking, for a given
message C and a prospective pad, P, out of a set of N pads which may
or may not be correct:
P(P|C) = N^-1
The length of C and the amount of ciphertexts given have no effect in
determining the key, nor is there any prospect of a know plaintext
attack as the pad is true random and the next bits are totally
independent of any others before them.
Of course the reason it is perfect is because there are many
different pads which give valid decryptions and there is no way of
knowing which one is correct.
IPG`s algorithm is definitely NOT an OTP and Don Wood is a snakeoil
merchant.
Datacomms Technologies web authoring and data security
Paul Bradley, Paul@fatmans.demon.co.uk
Paul@crypto.uk.eu.org, Paul@cryptography.uk.eu.org
Http://www.cryptography.home.ml.org/
Email for PGP public key, ID: 5BBFAEB1
"Don`t forget to mount a scratch monkey"
NODE 8e8f97cfRe: IPG Algorith Broken!
wichita@cyberstation.netSat, 30 Nov 1996 02:05:10 -0800 (PST)
On , 25 Nov 1996 paul@fatbrain.demon.co.uk wrote:
>
> > > Ahh... an OTP isn't unbreakable. Its just so encredibly breakable that
> > > you never know which break was the correct one ;)
> >
> > Note that Schneier says "perfect", not "unbreakable".
>
More gobbledegook about nothing. Yes it is perfect and yes it is
unbreakable!
snip......
>
> IPG`s algorithm is definitely NOT an OTP and Don Wood is a snakeoil
> merchant.
>
Play it Paul, (or is it Sam, or fatbrain).
Never has one person said so much and said nothing,
Lead on McPuff(ery)
With kindest regards,
Don Wood
NODE 40863959Re: IPG Algorith Broken!u
ichudov@algebra.com (Igor Chudov @ home)Sat, 30 Nov 1996 10:26:03 -0800 (PST)
wichita@cyberstation.net wrote:
> On , 25 Nov 1996 paul@fatbrain.demon.co.uk wrote:
> > > > Ahh... an OTP isn't unbreakable. Its just so encredibly breakable that
> > > > you never know which break was the correct one ;)
> > >
> > > Note that Schneier says "perfect", not "unbreakable".
> >
>
> More gobbledegook about nothing. Yes it is perfect and yes it is
> unbreakable!
Don, please look at my message that analyzes your algorithm in some
detail. I think that your algorithm is far from perfect because, among
other things, your system would leave about 1 out of 7 characters
unencrypted, and also because your A(JV) are not as good as you claim
them to be.
- Igor.
NODE b88acfe5Re: IPG Algorith Broken!
ichudov@algebra.com (Igor Chudov @ home)Tue, 26 Nov 1996 17:00:50 -0800 (PST)
paul@fatmans.demon.co.uk wrote:
> Perfect is a better term. Strictly speaking it is because there is no
> finite unicity distance (the amount of ciphertext with which the
> cipher can theoretically be broken). So, stricly speaking, for a given
> message C and a prospective pad, P, out of a set of N pads which may
> or may not be correct:
>
> P(P|C) = N^-1
What does it mean?
- Igor.
NODE 205f330fRe: IPG Algorith Broken!
wichita@cyberstation.netSat, 30 Nov 1996 02:15:40 -0800 (PST)
On Tue, 26 Nov 1996, Igor Chudov @ home wrote:
> paul@fatmans.demon.co.uk wrote:
> > Perfect is a better term. Strictly speaking it is because there is no
> > finite unicity distance (the amount of ciphertext with which the
> > cipher can theoretically be broken). So, stricly speaking, for a given
> > message C and a prospective pad, P, out of a set of N pads which may
> > or may not be correct:
> >
> > P(P|C) = N^-1
>
> What does it mean?
>
Yes, McPuff, what does it mean. Like all of your other pabulum, it does not
mean anything that has any significance to anyone living or yet to live.
I also greatly appreciate you defining unicity distance for me, I have
always wanted to know that.
With kindest regards,
Don Wood