NODE 24a42806I beg you, PLEASE prove that 0.123456789101112131415 is IRRATIONAL
Secret Squirrel <nobody@squirrel.owl.de>Sun, 19 Jan 1997 00:02:47 -0800 (PST)
Dear Cypher Punks,
I BEG YOU TO HELP ME!!!
Is it possible to prove that number 0.1234567891011121314151617181920...
iz irrational?
Or may be it is rational?
Also, another question for math geniuses here:
Is it REALLY true that there are real numbers that cannot be generated
by any algorithm? Some guy said that since the set of algorithms is
countable, but the set of real numbers is more than countable, there
must be some numbers for which there is no algorithms that generate them.
But I still do not believe him.
Also, is it true that the sequence of digits in e is random because the ONLY way to get to the
p'th digit is to calculate the p-1'st digits?
Also, is it the correct definition of a real number:
``A real number is the class of numbers which can represent the length of
an arbitrary line.''
I AM REAL DESPERATE FOR YOUR ASS ISTANCE.
NODE c53df740Re: I beg you, PLEASE prove that 0.123456789101112131415 is IRRATIONAL
snow <snow@smoke.suba.com>Sun, 19 Jan 1997 14:21:59 -0800 (PST)
> I BEG YOU TO HELP ME!!!
> Also, another question for math geniuses here:
> Is it REALLY true that there are real numbers that cannot be generated
> by any algorithm? Some guy said that since the set of algorithms is
> countable, but the set of real numbers is more than countable, there
> must be some numbers for which there is no algorithms that generate them.
x=0;
x1=0;
x++;
x--;
Would give you all int's, the only problem you have is granularity. In
practice, there are numbers which you can't get with algorythms, but in
theory you should be able to hit all real numbers of given granularity (i.e,
10 digits past the decimal point) with the right hardware and software. as in:
x=0.00000000001;
y=0.00000000001;
x1=x;
x=x+y;
x1=x1-y;
Should give you all real numbers with a granularity of 11 digits to the
right of the decimal point.
> I AM REAL DESPERATE FOR YOUR ASS ISTANCE.
HIBT?