NODE 24b51d2bnovice needing help
"Olivier Langlois" <olanglois@sympatico.ca>Tue, 11 Aug 1998 14:25:42 -0700 (PDT)
Hi,
I just started to read about cryptography and during my readings I found a
small problem
probably not very hard but I just don't know how to solve it. My number
theory knowledge is very limited.
a = b/c and
d = b/(b mod c)
I would like to demonstrate that gcd(a,d) = 1 and a*d>=b for any b and c
values(assuming b mod c != 0) is true or false through
logical induction.
Is there someone that could give me a hint ?
TIA
Olivier Langlois - olanglois@sympatico.ca -
http://www3.sympatico.ca/olanglois
Montreal, Canada
NODE 83896bb8Re: novice needing help
Xcott Craver <caj@math.niu.edu>Tue, 11 Aug 1998 15:46:11 -0700 (PDT)
On Tue, 11 Aug 1998, Olivier Langlois wrote:
> a = b/c and
> d = b/(b mod c)
I'm not sure what you're trying to say with this notation.
Well, if by '/' you mean integer division with truncation
(a la most programming languages,) then consider that
9 = 49/5 and
12 = 49/(49%5=4)
And so gcd(a,d) != 1.
This is my best guess as to what you're trying to say, since
in number-theoretic notation these two statements don't make
much sense: division is not closed on the integers, and
(b mod c) is not a single integer, but an equivalence class.
-Caj